← Back to Physics Formulas

Mechanics Formulas

Complete collection of mechanics formulas with detailed explanations, notation meanings, units, and real-world applications. Master the fundamentals of motion and forces.

🏃
⚖️

Newton's Laws of Motion

Newton's First Law (Law of Inertia)

∑F=0→a=0\sum F = 0 \rightarrow a = 0

An object at rest stays at rest, and an object in motion stays in motion unless acted upon by a net external force.

Notation:

00:Zero (no change in motion)
∑F\sum F:Net force (vector sum of all forces)
aa:Acceleration

Units:

FF:Newton (N) = kg·m/s²
aa:m/s²

Applications:

  • •Objects at rest on a table
  • •Satellites in orbit
  • •Car continuing to move after engine stops

Limitations:

Only applies in inertial reference frames

Newton's Second Law

F=maF = ma

The acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

Notation:

FF:Net force (vector)
mm:Mass of the object
aa:Acceleration (vector)

Units:

FF:Newton (N)
mm:Kilogram (kg)
aa:m/s²

Applications:

  • •Rocket propulsion
  • •Car acceleration
  • •Falling objects

Limitations:

Valid for speeds much less than speed of light

Newton's Third Law

F12=−F21F_{12} = -F_{21}

For every action, there is an equal and opposite reaction.

Notation:

F12F_{12}:Force exerted by object 1 on object 2
F21F_{21}:Force exerted by object 2 on object 1
−-:Negative sign indicates opposite direction

Units:

F12,F21F_{12}, F_{21}:Newton (N)

Applications:

  • •Rocket propulsion
  • •Walking
  • •Swimming

Limitations:

Forces act on different objects

🏃

Kinematics Equations

First Equation of Motion

v=v0+atv = v_0 + at

Final velocity equals initial velocity plus acceleration times time.

Notation:

vv:Final velocity
v0v_0:Initial velocity
aa:Acceleration
tt:Time

Units:

v,v0v, v_0:m/s
aa:m/s²
tt:s

Applications:

  • •Car acceleration
  • •Free fall
  • •Projectile motion

Limitations:

Constant acceleration only

Second Equation of Motion

s=v0t+12at2s = v_0t + \frac{1}{2}at^2

Displacement equals initial velocity times time plus half acceleration times time squared.

Notation:

ss:Displacement
v0v_0:Initial velocity
tt:Time
aa:Acceleration

Units:

ss:m
v0v_0:m/s
tt:s
aa:m/s²

Applications:

  • •Distance traveled by car
  • •Height of falling object
  • •Range of projectile

Limitations:

Constant acceleration, one-dimensional motion

Third Equation of Motion

v2=v02+2asv^2 = v_0^2 + 2as

Final velocity squared equals initial velocity squared plus twice acceleration times displacement.

Notation:

vv:Final velocity
v0v_0:Initial velocity
aa:Acceleration
ss:Displacement

Units:

v,v0v, v_0:m/s
aa:m/s²
ss:m

Applications:

  • •Braking distance
  • •Escape velocity
  • •Impact velocity

Limitations:

Constant acceleration, one-dimensional motion

⚡

Work and Energy

Work Done

W=F⋅s=Fscos⁡θW = F \cdot s = Fs \cos \theta

Work equals force times displacement times cosine of angle between them.

Notation:

WW:Work done
FF:Force
ss:Displacement
θ\theta:Angle between force and displacement

Units:

WW:Joule (J) = N·m
FF:N
ss:m
θ\theta:radians or degrees

Applications:

  • •Lifting objects
  • •Pushing a cart
  • •Spring compression

Limitations:

Force must be constant

Kinetic Energy

KE=12mv2KE = \frac{1}{2}mv^2

Kinetic energy equals half mass times velocity squared.

Notation:

KEKE:Kinetic energy
mm:Mass
vv:Velocity

Units:

KEKE:Joule (J)
mm:kg
vv:m/s

Applications:

  • •Moving vehicles
  • •Falling objects
  • •Collision analysis

Limitations:

Non-relativistic speeds

Gravitational Potential Energy

PE=mghPE = mgh

Gravitational potential energy equals mass times gravitational acceleration times height.

Notation:

PEPE:Potential energy
mm:Mass
gg:Gravitational acceleration
hh:Height

Units:

PEPE:Joule (J)
mm:kg
gg:m/s²
hh:m

Applications:

  • •Water in dam
  • •Roller coaster
  • •Falling objects

Limitations:

Near Earth's surface, constant g

Conservation of Mechanical Energy

KE+PE=constantKE + PE = \text{constant}

Total mechanical energy (kinetic plus potential) remains constant in the absence of non-conservative forces.

Notation:

KEKE:Kinetic energy
PEPE:Potential energy
constant\text{constant}:Total mechanical energy

Units:

KE,PE,constantKE, PE, \text{constant}:Joule (J)

Applications:

  • •Pendulum motion
  • •Roller coaster
  • •Spring-mass system

Limitations:

Only conservative forces present

💥

Momentum and Collisions

Linear Momentum

p=mvp = mv

Momentum equals mass times velocity.

Notation:

pp:Momentum (vector)
mm:Mass
vv:Velocity (vector)

Units:

pp:kg·m/s
mm:kg
vv:m/s

Applications:

  • •Collision analysis
  • •Rocket propulsion
  • •Sports physics

Limitations:

Non-relativistic speeds

Conservation of Momentum

∑pinitial=∑pfinal\sum p_{\text{initial}} = \sum p_{\text{final}}

Total momentum of a system remains constant if no external forces act on it.

Notation:

∑pinitial\sum p_{\text{initial}}:Sum of initial momenta
∑pfinal\sum p_{\text{final}}:Sum of final momenta

Units:

∑pinitial,∑pfinal\sum p_{\text{initial}}, \sum p_{\text{final}}:kg·m/s

Applications:

  • •Elastic collisions
  • •Inelastic collisions
  • •Explosions

Limitations:

No external forces on system

Impulse

J=FΔt=ΔpJ = F\Delta t = \Delta p

Impulse equals force times time interval, which equals change in momentum.

Notation:

JJ:Impulse
FF:Average force
Δt\Delta t:Time interval
Δp\Delta p:Change in momentum

Units:

JJ:N·s = kg·m/s
FF:N
Δt\Delta t:s
Δp\Delta p:kg·m/s

Applications:

  • •Car crashes
  • •Baseball hits
  • •Airbag deployment

Limitations:

Constant force approximation

🔄

Circular Motion

Centripetal Force

Fc=mv2rF_c = \frac{mv^2}{r}

Centripetal force equals mass times velocity squared divided by radius.

Notation:

FcF_c:Centripetal force
mm:Mass
vv:Tangential velocity
rr:Radius of circular path

Units:

FcF_c:N
mm:kg
vv:m/s
rr:m

Applications:

  • •Car turning
  • •Satellite orbits
  • •Amusement park rides

Limitations:

Uniform circular motion

Angular Velocity

ω=vr=2πf\omega = \frac{v}{r} = 2\pi f

Angular velocity equals tangential velocity divided by radius, or 2π times frequency.

Notation:

ω\omega:Angular velocity
vv:Tangential velocity
rr:Radius
ff:Frequency

Units:

ω\omega:rad/s
vv:m/s
rr:m
ff:Hz

Applications:

  • •Rotating objects
  • •Planetary motion
  • •Centrifuges

Limitations:

Uniform circular motion

Centripetal Acceleration

ac=v2r=ω2ra_c = \frac{v^2}{r} = \omega^2 r

Centripetal acceleration equals velocity squared divided by radius, or angular velocity squared times radius.

Notation:

aca_c:Centripetal acceleration
vv:Tangential velocity
rr:Radius
ω\omega:Angular velocity

Units:

aca_c:m/s²
vv:m/s
rr:m
ω\omega:rad/s

Applications:

  • •Banked curves
  • •Artificial gravity
  • •Centrifugal separators

Limitations:

Uniform circular motion

🌍

Gravitation

Universal Law of Gravitation

F=Gm1m2r2F = G\frac{m_1 m_2}{r^2}

Gravitational force between two masses equals gravitational constant times product of masses divided by distance squared.

Notation:

FF:Gravitational force
GG:Gravitational constant
m1,m2m_1, m_2:Masses of objects
rr:Distance between centers

Units:

FF:N
GG:6.674 × 10⁻¹¹ N·m²/kg²
m1,m2m_1, m_2:kg
rr:m

Applications:

  • •Planetary motion
  • •Satellite orbits
  • •Tides

Limitations:

Point masses or spherical objects

Gravitational Field Strength

g=GMr2g = \frac{GM}{r^2}

Gravitational field strength equals gravitational constant times mass divided by distance squared.

Notation:

gg:Gravitational field strength
GG:Gravitational constant
MM:Mass of central body
rr:Distance from center

Units:

gg:m/s²
GG:N·m²/kg²
MM:kg
rr:m

Applications:

  • •Weight on different planets
  • •Satellite motion
  • •Escape velocity

Limitations:

Spherical mass distribution

Escape Velocity

vescape=2GMrv_{\text{escape}} = \sqrt{\frac{2GM}{r}}

Escape velocity equals square root of twice gravitational constant times mass divided by radius.

Notation:

vescapev_{\text{escape}}:Escape velocity
GG:Gravitational constant
MM:Mass of central body
rr:Radius from center

Units:

vescapev_{\text{escape}}:m/s
GG:N·m²/kg²
MM:kg
rr:m

Applications:

  • •Rocket launches
  • •Black hole physics
  • •Space exploration

Limitations:

No air resistance, spherical body

Practice Problems

  • 📝Calculate force needed to accelerate 2 kg mass at 3 m/s²
  • 📝Find kinetic energy of 5 kg object moving at 10 m/s
  • 📝Calculate centripetal force for 1 kg mass in 2m radius at 5 m/s

Study Tips

  • 💡Always check units for consistency
  • 💡Draw free-body diagrams for force problems
  • 💡Use energy conservation when possible