Coulomb's Law Calculator

Calculate the electrostatic force between two point charges with interactive animation

Parameters

Cⓘ
Cⓘ
mⓘ
Show Trail

Controls

xⓘ

Calculated Values

Force Magnitude:
0.90;N0.90;N
k/r² factor:
899000000000.00;N/C2899000000000.00;N/C²

Examples

Two 1 μC charges, 10 cm apart

Like charges — repulsive force magnitude.

  • Force Magnitude: 0.900.90

±1 μC, 20 cm apart

Opposite charges — same magnitude, attractive.

  • Force Magnitude: 0.220.22

Visualization

Coulomb's Law — Electrostatic Force Between Point Charges

Electrostatic force is the mutual force between two stationary point charges. Coulomb's law (1785) states that the magnitude is proportional to |q₁q₂| and inversely proportional to r², where r is the center-to-center distance.

In SI units, F = (1/(4πε₀))·|q₁q₂|/r² with ε₀ ≈ 8.85×10⁻¹² F/m. The Coulomb constant k = 1/(4πε₀) ≈ 8.99×10⁹ N·m²/C². In a dielectric medium, replace ε₀ with ε = κε₀ (κ = relative permittivity).

Direction: like charges repel (force pushes apart along the line joining them); unlike charges attract. Newton's third law: the force on q₁ equals and opposes the force on q₂.

Superposition principle: the net force on a charge from many others is the vector sum of individual Coulomb forces. This is the basis for calculating fields from charge distributions.

Validity: exact for point charges; for spherically symmetric distributions (e.g. uniform shell), use total charge at center when field point is outside. Breaks down at r → 0 for extended bodies.

Comparison with gravity: both are inverse-square central forces, but electrostatic force can be attractive or repulsive and is vastly stronger for elementary charges (e.g. two protons: F_e/F_g ~ 10³⁶).

Key Concepts

  • F = k|q₁q₂|/r² — scalar magnitude
  • k ≈ 8.99×10⁹ N·m²/C²; k = 1/(4πε₀)
  • Vector form: F⃗₁₂ = k q₁q₂/r̂₁₂ r²
  • Inverse square: F → F/4 when r doubles
  • Superposition: F⃗_net = Σ F⃗_i
  • Medium: multiply by 1/κ or use ε = κε₀

Real-World Applications

  • Electrostatic precipitators (dust removal in power plants)
  • Ink-jet printing and paint electrostatic spraying
  • Van de Graaff generator demonstrations
  • Ionic bonding models in chemistry
  • Class 11–12 NCERT/CBSE electrostatics problems
  • Particle accelerator beam focusing (qualitative)

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Physics Equations

Coulomb's Law:
F=k∣q1q2∣r2F = k\frac{|q_1 q_2|}{r^2}
Coulomb Constant:
k=14πε0≈8.99×109k = \frac{1}{4\pi\varepsilon_0} \approx 8.99 \times 10^9

Step-by-Step Solution

See how the main results are calculated.

1

Step 1: Identify Given Quantities

Write down charges and separation with SI units (coulombs, meters).

Result:

q1=0.000001 C,q2=−0.000001 C,r=0.1 mq_1 = 0.000001 \text{ C}, \quad q_2 = -0.000001 \text{ C}, \quad r = 0.1 \text{ m}

Explanation:

Coulomb's law applies to two point charges separated by distance r between their centers. Use SI units throughout.

2

Step 2: Write Coulomb Constant

Use k = 1/(4πε₀) in vacuum.

Equation:

k=14πε0≈8.99×109 N\cdotpm2/C2k = \frac{1}{4\pi\varepsilon_0} \approx 8.99 \times 10^9 \text{ N·m}^2/\text{C}^2

Explanation:

ε₀ ≈ 8.85×10⁻¹² F/m. In a dielectric medium, replace k with k/κ where κ is relative permittivity.

3

Step 3: Compute Charge Product

Multiply magnitudes of the two charges.

Calculation:

∣q1q2∣=∣0.000001×−0.000001∣=1.0000e−12 C2|q_1 q_2| = |0.000001 \times -0.000001| = 1.0000e-12 \text{ C}^2

Result:

∣q1q2∣=1.0000e−12C2|q_1 q_2| = 1.0000e-12 C²

Explanation:

Magnitude formula uses absolute value of product; sign determines attraction vs repulsion separately.

4

Step 4: Square the Distance

Inverse-square law requires r² in the denominator.

Calculation:

r2=(0.1)2=0.010000 m2r^2 = (0.1)^2 = 0.010000 \text{ m}^2

Result:

r2=0.010000m2r² = 0.010000 m²

Explanation:

Doubling distance increases r² by 4×, reducing force to ¼ — characteristic of inverse-square laws.

5

Step 5: Apply Coulomb's Law

Equation:

F=k∣q1q2∣r2F = k\frac{|q_1 q_2|}{r^2}

Calculation:

F=(8.99×109)×1.0000e−120.010000F = (8.99 \times 10^9) \times \frac{1.0000e-12}{0.010000}
F=8.9900e−1 NF = 8.9900e-1 \text{ N}

Result:

F=8.9900e−1NF = 8.9900e-1 N

Explanation:

This is the magnitude of the electrostatic force on each charge (Newton's third law: equal and opposite forces).

6

Step 6: Determine Force Direction

Classify interaction as attractive or repulsive.

Result:

Attractive (unlike charges)

Explanation:

Opposite signs → charges attract along the line joining them.

Frequently Asked Questions (FAQ)

Why inverse-square law?

Field lines from a point charge spread uniformly on a sphere of area 4πr², so field strength E ∝ 1/r² and force F = qE follows the same dependence.

Can Coulomb force be negative?

We usually quote magnitude F = k|q₁q₂|/r². Sign in vector form encodes attraction (opposite signs) vs repulsion (same signs).

What if charges are not point-like?

Use superposition or Gauss's law. For uniform spheres, treat as point charge at center when outside the sphere.

Does Coulomb's law work for moving charges?

Not exactly — moving charges create magnetic fields; electrostatic formula applies when charges are approximately stationary (quasi-static).

How does ε₀ relate to k?

k = 1/(4πε₀). ε₀ is the permittivity of free space, a fundamental constant in Maxwell's equations.

Practice MCQs

  1. If distance between two point charges doubles, the force becomes:
  2. The SI unit of the Coulomb constant k is:
  3. Two positive charges experience a force that is:
  4. Coulomb's law is most accurate when:
  5. Compared to gravity between two protons, electrostatic repulsion is:
  6. In a medium with κ = 4, the force between two charges compared to vacuum is: