Voltage Divider Calculator

Find output voltage and current in a two-resistor voltage divider

Parameters

Vⓘ
Ωⓘ
Ωⓘ
Show Trail

Controls

xⓘ

Calculated Values

Output Voltage:
8.00;V8.00;V
Circuit Current:
0.00;A0.00;A
Power in R₁:
0.02;W0.02;W

Examples

12 V, 1 kΩ + 2 kΩ

Output across 2 kΩ.

  • Output Voltage: 8.008.00

5 V, equal 10 kΩ resistors

Half supply at midpoint.

  • Output Voltage: 2.502.50

Visualization

Voltage Divider — Potential Division in Series Resistors

A voltage divider (potential divider) is two or more resistors in series across a voltage source. The output voltage is taken across one resistor — typically R₂ between the junction and ground.

Because resistors are in series, the same current I = V_in/(R₁+R₂) flows through both. Ohm's law on R₂ gives V_out = I·R₂ = V_in·R₂/(R₁+R₂).

The fraction of input appearing at output is the voltage divider ratio: η = R₂/(R₁+R₂). For R₁ = R₂, V_out = V_in/2. For R₂ >> R₁, V_out → V_in; for R₂ << R₁, V_out → 0.

Loading effect: a real load R_L in parallel with R₂ reduces effective resistance R₂||R_L, lowering V_out. Design rule: R_L >> R₂ (often 10×–100×) for less than ~10% error.

Thevenin equivalent at output: V_th = V_out (open circuit) and R_th = R₁||R₂. Use this when analyzing loaded dividers or connecting to amplifier inputs.

Power: P₁ = I²R₁ and P₂ = I²R₂. Total P = V_in²/(R₁+R₂). Lower current (larger resistors) saves power but increases sensitivity to loading and noise.

Key Concepts

  • V_out = V_in × R₂/(R₁ + R₂)
  • I = V_in/(R₁ + R₂) — identical in both resistors
  • Divider ratio η = R₂/(R₁+R₂)
  • Loaded output: use R₂_eff = R₂∥R_L
  • Thevenin: V_th = V_out, R_th = R₁∥R₂
  • Never exceed V_in with passive resistors only

Real-World Applications

  • Microcontroller ADC reference scaling (0–3.3 V from 5 V)
  • Transistor base biasing networks
  • Potentiometer as adjustable divider
  • Sensor signal conditioning
  • Logic level translation between IC families

Explore Further

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  • RC Circuits

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  • Power Calculator

    Calculate electrical power, energy consumption, and efficiency.

  • Series Circuit

    Analyze series circuits with total resistance, current, and voltage drops.

  • Parallel Circuit

    Analyze parallel circuits with current division and total resistance.

Physics Equations

Output Voltage:
Vout=VinR2R1+R2V_{out} = V_{in} \frac{R_2}{R_1 + R_2}
Current:
I=VinR1+R2I = \frac{V_{in}}{R_1 + R_2}

Step-by-Step Solution

See how the main results are calculated.

1

Step 1: Recognize Circuit Topology

R₁ and R₂ are in series; V_out is taken across R₂.

Explanation:

Current has only one path: through R₁, then R₂. Output voltage is the potential drop across R₂.

2

Step 2: Total Series Resistance

Equation:

Rtotal=R1+R2R_{total} = R_1 + R_2

Calculation:

Rtotal=1000+2000=3000 ΩR_{total} = 1000 + 2000 = 3000 \text{ Ω}

Result:

Rtotal=3000ΩR_total = 3000 Ω

Explanation:

Series resistances add directly because the same current passes through each.

3

Step 3: Find Series Current (Ohm's Law)

Equation:

I=VinRtotalI = \frac{V_{in}}{R_{total}}

Calculation:

I=123000=0.004000 AI = \frac{12}{3000} = 0.004000 \text{ A}

Result:

I=0.004000AI = 0.004000 A

Explanation:

This current flows through both R₁ and R₂ (and would flow through any series elements).

4

Step 4: Voltage Across R₂

Equation:

Vout=I×R2V_{out} = I \times R_2

Calculation:

Vout=0.004000×2000=8.000000 VV_{out} = 0.004000 \times 2000 = 8.000000 \text{ V}

Result:

Vout=8.000000VV_out = 8.000000 V

Explanation:

Ohm's law on R₂ gives the output voltage directly from current and resistance.

5

Step 5: Verify with Divider Formula

Equation:

Vout=Vin×R2R1+R2V_{out} = V_{in} \times \frac{R_2}{R_1 + R_2}

Calculation:

Vout=12×20003000=12×0.6667=8.000000 VV_{out} = 12 \times \frac{2000}{3000} = 12 \times 0.6667 = 8.000000 \text{ V}

Result:

Dividerratioη=66.67Divider ratio η = 66.67%

Explanation:

The fraction R₂/(R₁+R₂) is the voltage divider ratio — useful for design without finding current first.

6

Step 6: Power Dissipation (Optional Check)

Equation:

P=I2RP = I^2 R

Calculation:

P1=0.0160 W,P2=0.0320 W,Ptotal=0.0480 WP_1 = 0.0160 \text{ W}, \quad P_2 = 0.0320 \text{ W}, \quad P_{total} = 0.0480 \text{ W}

Explanation:

Total power from source equals V_in × I. Power splits between resistors proportionally to resistance.

Frequently Asked Questions (FAQ)

Can I get V_out > V_in?

Not with a passive two-resistor divider. Active circuits (op-amps) can boost voltage.

What resistor values should I choose?

Balance: lower R → more current and power; higher R → more loading sensitivity. Often 1 kΩ–100 kΩ for signals.

Why is my measured V_out lower than calculated?

Usually loading (meter or next stage draws current) or tolerance in R₁, R₂.

Three-resistor divider?

Chain dividers: treat each tap similarly; V at each node = V_in × (resistance below node)/(total R).

Does frequency matter?

At DC and low frequency, yes. At high frequency, parasitic capacitance can form another divider with R.

Practice MCQs

  1. With fixed R₁, increasing R₂ will:
  2. If R₁ = R₂ = 1 kΩ and V_in = 12 V, then V_out is:
  3. A heavy load (small R_L) in parallel with R₂ tends to:
  4. Current through R₁ and R₂ in an unloaded divider is:
  5. V_out can never be greater than V_in because:
  6. Thevenin resistance seen at V_out terminals is: