Continuity Equation Calculator

Find v₂ from A₁v₁ = A₂v₂ for incompressible flow

Parameters

m²ⓘ
m/sⓘ
m²ⓘ
Show Trail

Controls

xⓘ

Calculated Values

Velocity 2:
4.00;m/s4.00;m/s
Volume Flow Rate Q:
0.02;m3/s0.02;m³/s

Examples

Pipe reduction

D₁=0.1 m v₁=2 m/s, D₂=0.05 m.

    Known Q

    A=0.01 m², v=3 m/s.

      Visualization

      Continuity Equation — Conservation of Mass in Flow

      The continuity equation expresses conservation of mass for fluid flow. For steady flow through a pipe or streamtube with no internal sources or sinks, the mass flow rate ṁ = ρAv must be constant. For incompressible liquids (water, oil at moderate pressure changes), density ρ is constant and the volumetric flow rate Q = Av is constant: A₁v₁ = A₂v₂.

      Physically: fluid cannot accumulate or disappear inside a sealed pipe — what enters one cross-section per second must leave another. When the pipe narrows (smaller A), the fluid must speed up (larger v) to pass the same volume per second. This is why covering a hose outlet with your thumb produces a fast, narrow jet.

      For circular pipes, A = πD²/4. Halving the diameter D reduces area by factor 4 (since A ∝ D²), so velocity increases by factor 4 for the same Q. Example: Q = 0.01 m³/s in D = 0.1 m pipe gives v ≈ 1.27 m/s; reducing to D = 0.05 m gives v ≈ 5.1 m/s.

      The average velocity v = Q/A is used in engineering calculations. In laminar pipe flow, the velocity profile is parabolic with v_max = 2v_avg at the center. In turbulent flow, the profile is flatter but continuity still holds for the average.

      For compressible gases (air ducts, nozzles), use ṁ = ρ₁A₁v₁ = ρ₂A₂v₂ — density changes with pressure and temperature. At low Mach numbers (ΔP small compared to pressure), air is often treated as incompressible in building HVAC.

      Continuity is one of three pillars of pipe flow analysis, together with Bernoulli (energy) and momentum. It explains the Venturi effect when combined with Bernoulli: constriction → higher v → lower P.

      Key Concepts

      • Q = Av = constant (incompressible)
      • A₁v₁ = A₂v₂; ṁ = ρAv (compressible)
      • Narrow section → higher average velocity
      • A = πD²/4; halving D → 4× velocity
      • v_avg = Q/A (not always centerline speed)
      • Steady flow: ∂/∂t terms zero at fixed point

      Real-World Applications

      • Garden hose and fire hose nozzle jets
      • Blood flow in arteries (with Bernoulli for pressure)
      • Venturi, orifice, and rotameter flow meters
      • Water supply and sewage pipe network sizing
      • Class 11–12 continuity and equation of continuity
      • River choke points and channel constriction

      Explore Further

      More fluid mechanics tools

      Physics Equations

      Continuity:
      A1v1=A2v2=QA_1 v_1 = A_2 v_2 = Q
      Velocity 2:
      v2=A1v1A2v_2 = \frac{A_1 v_1}{A_2}

      Step-by-Step Solution

      See how the main results are calculated.

      1

      Step 1: Continuity (Incompressible)

      Equation:

      A1v1=A2v2=QA_1 v_1 = A_2 v_2 = Q

      Explanation:

      Mass conservation: volume flow rate Q constant.

      2

      Step 2: Areas

      Calculation:

      A1=1.0000e−2 m2,A2=5.0000e−3 m2A_1 = 1.0000e-2 \text{ m}^2, \quad A_2 = 5.0000e-3 \text{ m}^2

      Explanation:

      A = πD²/4 for circular pipes.

      3

      Step 3: Solve v₂

      Calculation:

      v2=A1v1A2=0.01×20.005=4.0000 m/sv_2 = \frac{A_1 v_1}{A_2} = \frac{0.01 \times 2}{0.005} = 4.0000 \text{ m/s}

      Result:

      v2=4.0000m/sv₂ = 4.0000 m/s
      4

      Step 4: Volume Flow Rate

      Calculation:

      Q=A1v1=2.0000e−2 m3/sQ = A_1 v_1 = 2.0000e-2 \text{ m}^3\text{/s}

      Result:

      Q=2.0000e−2m3/sQ = 2.0000e-2 m³/s
      5

      Step 5: Trend

      Smaller area → higher speed.

      Explanation:

      A₂ < A₁ ⇒ v₂ > v₁.

      6

      Step 6: Assumptions

      Steady, incompressible, no leaks.

      Explanation:

      Compressible flow needs different relation.

      Frequently Asked Questions (FAQ)

      Average vs centerline velocity?

      Use average v = Q/A; parabolic profile has v_max = 2v_avg (laminar pipe).

      Multiple inlets?

      Σ Q_in = Σ Q_out for control volume.

      Air in ducts?

      Often treat as incompressible if ΔP small; else use ρAv.

      Link to Bernoulli?

      Continuity + energy → Bernoulli equation.

      Turbulent flow?

      Continuity still holds; velocity profile affects average v.

      Practice MCQs

      1. Pipe narrows to half diameter, area becomes:
      2. If A₂ = A₁/4, then v₂ is:
      3. Continuity expresses conservation of:
      4. Units of Q = Av:
      5. Steady flow means:
      6. Water is approximately: