Hydrostatic Pressure Calculator
Find gauge pressure at depth h in a fluid: P = ρgh
Parameters
Controls
Calculated Values
Examples
Pool depth 3 m
Water ρ=1000, h=3 m.
- P:
Oil tank 5 m
ρ=850 kg/m³.
Visualization
Hydrostatic Pressure — Pressure in Static Fluids
Hydrostatic pressure is the pressure exerted by a fluid at rest due to the weight of the fluid column above a point. For an incompressible fluid with constant density ρ, the gauge pressure at vertical depth h below a free surface is P = ρgh, where g ≈ 9.81 m/s². This is one of the most fundamental results in fluid statics, derived from balancing vertical forces on a fluid element: dP = ρg dh.
Gauge pressure is measured relative to the local atmospheric pressure P_atm ≈ 101.325 kPa (14.7 psi, 1 bar). Absolute pressure includes atmospheric head: P_abs = P_atm + ρgh for a tank open to the atmosphere. In a continuous static fluid, pressure is the same at every point on the same horizontal level — this explains why water seeks a common level in connected vessels (communicating vessels).
Numerical reference (water, ρ = 1000 kg/m³): P ≈ 9.81 kPa per meter of depth (~98 kPa at 10 m, ~1 bar). Scuba divers feel ~2 atm absolute at 10 m depth (1 atm water + 1 atm air). Mercury barometers use ρ_Hg ≈ 13,600 kg/m³ so 760 mm Hg ≈ 1 atm in a compact column. Oil (ρ ≈ 850 kg/m³) gives lower pressure than water at the same depth.
The hydrostatic paradox demonstrates that pressure at a point depends on vertical depth h, not on the shape or total volume of fluid above — a narrow tall column and a wide shallow basin at the same water level exert the same pressure at the bottom. This is essential for dam, tank, and submarine hull design.
Pressure increases linearly with h, so the force on a vertical wall is found by integrating the triangular pressure distribution (see Hydrostatic Force calculator). For large vertical extents of gas, density varies with height and the isothermal barometric formula P = P₀ exp(−Mgh/RT) replaces ρgh.
Engineering conversions: 1 Pa = 1 N/m²; 1 kPa = 1000 Pa; 1 bar = 10⁵ Pa; 1 psi ≈ 6895 Pa. Blood pressure in mmHg is a direct hydrostatic column tradition (133.3 Pa per mmHg).
Key Concepts
- P_gauge = ρgh below free surface
- P_abs = P_atm + ρgh (open tank)
- Same pressure at same horizontal level
- Water: ~9.81 kPa per meter depth
- Hydrostatic paradox: depth h, not volume
- dP/dh = ρg (linear P–h slope)
Real-World Applications
- Dam, reservoir, and swimming pool wall design
- Scuba and saturation diving pressure limits
- Mercury and aneroid barometers
- Submarine and ROV hull pressure rating
- Class 11–12 NCERT fluid statics and Pascal's law
- Pressure sensors and depth gauges in wells
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Physics Equations
Step-by-Step Solution
See how the main results are calculated.
Step 1: Hydrostatic Law
Equation:
Explanation:
Pressure at depth h in a static fluid of density ρ.
Step 2: Given Values
Result:
Explanation:
Use consistent SI units.
Step 3: Multiply ρgh
Calculation:
Result:
Step 4: Convert to kPa
Calculation:
Explanation:
1 kPa = 1000 Pa.
Step 5: Gauge vs Absolute
Add atmospheric pressure for absolute.
Explanation:
P_abs = P_atm + ρgh for open tanks.
Step 6: Linear with Depth
Pressure increases linearly with h.
Explanation:
Doubling depth doubles gauge pressure.
Frequently Asked Questions (FAQ)
Gauge vs absolute?
Gauge = P − P_atm. Absolute includes atmospheric head.
Does shape of tank matter?
Only depth h and ρ matter for P at a point.
Why mercury in barometers?
High ρ → manageable column height (~760 mm).
g on Moon?
Use local g; hydrostatic P lower for same h.
Compressible air?
ρ varies with height; ideal ρgh fails over large Δh.
Practice MCQs
- Doubling depth h in same fluid doubles:
- Hydrostatic pressure formula:
- At same depth in connected vessels, pressure is:
- Gauge pressure at surface of open lake is approximately:
- Heavier fluid (larger ρ) at same h gives:
- SI unit of pressure:
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