Optical Path Difference Calculator

Find OPD = 2nt for normal incidence on a thin film

Parameters

ⓘ
nmⓘ
nmⓘ
Show Trail

Controls

xⓘ

Calculated Values

OPD:
828.00;nm828.00;nm
Order m = OPD/λ:
1.51;1.51;

Examples

n=1.38, t=300 nm

Coating on glass.

    Visualization

    Optical Path Difference (Thin Films)

    Optical path length OPL = n × geometric path. For normal incidence on a thin film of thickness t and index n, round-trip OPD = 2nt. Interference with reflected waves depends on OPD relative to wavelength.

    Bright (constructive) or dark (destructive) fringes also depend on 180° phase shifts at interfaces (low-to-high index reflection adds λ/2 effective path).

    Anti-reflection coatings use quarter-wave thickness t = λ/(4n) on glass to cancel reflected light. Soap bubbles and oil slicks show color from wavelength-dependent interference.

    OPD = mλ gives constructive (with phase rules); OPD = (m + ½)λ destructive. Multiple reflections in thick films require more detailed analysis.

    Connects to Young experiment: both are superposition of waves with path difference determining intensity.

    Key Concepts

    • OPD = 2nt (normal incidence)
    • OPL = n × path
    • Phase shift at interface
    • Quarter-wave AR coating
    • Constructive vs destructive

    Real-World Applications

    • Anti-reflection coatings
    • Soap film colors
    • Oil on water patterns
    • Optical interferometry
    • Thin-film filters

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    Physics Equations

    OPD:
    OPD=2ntOPD = 2nt

    Step-by-Step Solution

    See how the main results are calculated.

    1

    Step 1: Optical Path

    Equation:

    OPD=2ntOPD = 2nt

    Explanation:

    Normal incidence thin film; factor 2 for round trip.

    2

    Step 2: Values

    Result:

    n=1.38,t=300nm,λ=550nmn = 1.38, t = 300 nm, λ = 550 nm
    3

    Step 3: OPD

    Calculation:

    OPD=2×1.38×3.0000e−7=8.2800e−7 m=828.00 nmOPD = 2\times1.38\times3.0000e-7 = 8.2800e-7\text{ m} = 828.00\text{ nm}
    4

    Step 4: Order

    Calculation:

    m=OPD/λ=1.5055m = OPD/\lambda = 1.5055

    Explanation:

    Integer m → constructive (with phase rules).

    5

    Step 5: Phase Shift

    180° shift possible at boundaries.

    Explanation:

    Low-n to high-n reflection may add λ/2.

    6

    Step 6: Applications

    Anti-reflection coatings, soap films, oil slicks.

    Explanation:

    Thickness tuned to cancel reflected light.

    Frequently Asked Questions (FAQ)

    Why factor 2?

    Light reflects from top and bottom of film — round trip.

    Oblique incidence?

    OPD = 2nt cos θ (internal angle); this tool uses normal incidence.

    Practice MCQs

    1. OPD for thin film (normal):
    2. AR coating thickness ~
    3. Higher n in film:
    4. Soap colors from:
    5. Reflection at low to high n:
    6. OPD = mλ typically means: