Adiabatic Process Calculator

Find P₂ and T₂ for reversible adiabatic ideal gas (Q = 0)

Parameters

barⓘ
Lⓘ
Lⓘ
ⓘ
Kⓘ
Show Trail

Controls

xⓘ

Calculated Values

Final Pressure P₂:
0.38;bar0.38;bar
Final Temperature T₂:
227.36;K227.36;K
Work (bar·L scale):
6.05;bar⋅L6.05;bar·L

Examples

Air compression

P₁=1 bar, V₁=10 L, V₂=5 L, γ=1.4.

    Expansion to double volume

    Same P₁,V₁, V₂=20 L.

      Visualization

      Adiabatic Processes — No Heat Exchange (Q = 0)

      An adiabatic process is one with no heat transfer across the system boundary: Q = 0. This occurs in perfectly insulated systems, or when the process is so rapid that negligible heat flows in or out (e.g. sound waves, quick compression in a diesel engine). The first law reduces to ΔU = −W.

      For a reversible quasistatic adiabatic process of an ideal gas with constant heat capacities, the process equations are: PV^γ = constant, TV^(γ−1) = constant, and TP^((1−γ)/γ) = constant, where γ = C_p/C_v is the heat capacity ratio (adiabatic index).

      During adiabatic expansion, the gas does positive work on the surroundings, internal energy decreases, and temperature falls — this is why expanding spray cans feel cold. Adiabatic compression does work on the gas, raising T (bicycle pump heating). On a P–V diagram, an adiabat is steeper than an isotherm because γ > 1.

      Typical γ values: monatomic ideal gas γ = 5/3 ≈ 1.67; diatomic (N₂, O₂, air at room T) γ ≈ 1.4; polyatomic and water vapor γ closer to 1.33. For ideal gas, Mayer's relation gives C_p − C_v = R and γ = 1 + R/C_v.

      Reversible adiabatic work between states 1 and 2: W = (P₁V₁ − P₂V₂)/(γ − 1) = nR(T₁ − T₂)/(γ − 1). For γ = 1.4 and volume doubling (V₂ = 2V₁), P₂/P₁ = 2^(−γ) ≈ 0.38 and T₂/T₁ = 2^(1−γ) ≈ 0.76.

      Adiabatic is not the same as isentropic for irreversible processes, but reversible adiabatic ideal gas processes are isentropic (ΔS = 0). Real irreversible adiabatic expansions (e.g. Joule–Thomson throttling) may not follow PV^γ relations exactly.

      Key Concepts

      • Q = 0 ⇒ ΔU = −W (all energy change from work)
      • PV^γ = const; γ = C_p/C_v (adiabatic index)
      • Expansion: T and P decrease; compression: T and P increase
      • Adiabat steeper than isotherm on P–V diagram
      • W_rev = (P₁V₁ − P₂V₂)/(γ − 1)
      • Reversible adiabatic ideal gas ⇒ isentropic (ΔS = 0)

      Real-World Applications

      • Diesel engine compression ignition (rapid compression heats air)
      • Meteorology: dry adiabatic lapse rate (~9.8 K/km for rising air)
      • Sound propagation in air (adiabatic compressions/rarefactions)
      • Insulated gas cylinder and cryogenic expansion cooling
      • Class 12 derivations of adiabatic relations from first law + PV^γ
      • Chinook/foehn wind warming from adiabatic descent of air

      Explore Further

      More thermodynamics tools

      Physics Equations

      Adiabatic P–V:
      P1V1γ=P2V2γP_1 V_1^\gamma = P_2 V_2^\gamma
      Adiabatic T–V:
      T1V1γ−1=T2V2γ−1T_1 V_1^{\gamma-1} = T_2 V_2^{\gamma-1}

      Step-by-Step Solution

      See how the main results are calculated.

      1

      Step 1: Adiabatic Condition

      No heat exchange: Q = 0.

      Equation:

      Q=0⇒ΔU=−WQ = 0 \Rightarrow \Delta U = -W

      Explanation:

      Insulated or fast process — no time for heat transfer.

      2

      Step 2: Relation P–V

      Equation:

      P1V1γ=P2V2γP_1 V_1^\gamma = P_2 V_2^\gamma

      Explanation:

      For reversible adiabatic ideal gas.

      3

      Step 3: Find P₂

      Calculation:

      P2=P1(V1V2)γ=1×(0.5000)1.4=0.3789P_2 = P_1 \left(\frac{V_1}{V_2}\right)^\gamma = 1 \times (0.5000)^{1.4} = 0.3789

      Result:

      P2=0.3789(sameunitsasP1)P₂ = 0.3789 (same units as P₁)
      4

      Step 4: Temperature Relation

      Equation:

      T1V1γ−1=T2V2γ−1T_1 V_1^{\gamma-1} = T_2 V_2^{\gamma-1}

      Calculation:

      T2=300×(0.5000)0.3999999999999999=227.36 KT_2 = 300 \times (0.5000)^{0.3999999999999999} = 227.36 \text{ K}

      Result:

      T2=227.36KT₂ = 227.36 K
      5

      Step 5: Work (ideal gas)

      Equation:

      W=P1V1−P2V2γ−1W = \frac{P_1 V_1 - P_2 V_2}{\gamma - 1}

      Explanation:

      Expansion cools the gas (T₂ < T₁ for expansion).

      6

      Step 6: γ Values

      Common heat capacity ratio γ = C_p/C_v.

      Explanation:

      Monatomic: 1.67; diatomic: 1.4; air ≈ 1.4.

      Frequently Asked Questions (FAQ)

      Is adiabatic the same as insulated?

      Insulated implies adiabatic ideally; real insulation has small heat leak.

      Why does pumped bicycle tire get hot?

      Rapid compression — adiabatic-like, work on gas raises T.

      Reversible vs irreversible adiabatic?

      PV^γ relations apply to reversible quasistatic case; irreversible still has Q=0 but different final states.

      Can adiabatic process be isothermal?

      Only if no work and Q=0 trivially; nontrivial expansion always changes T.

      How to find γ experimentally?

      Measure C_p and C_v or use γ = C_p/C_v from gas type.

      Practice MCQs

      1. Adiabatic expansion of ideal gas:
      2. γ for monatomic ideal gas:
      3. Along adiabat on PV diagram, curve is:
      4. Q in adiabatic process:
      5. Rapid compression in insulated cylinder is approximately:
      6. For γ = 1.4, if volume doubles, pressure ratio P₂/P₁ is about: