Isothermal Process Calculator
Calculate work W and heat Q for isothermal ideal gas (ΔU = 0)
Parameters
Controls
Calculated Values
Examples
1 mol at 300 K, double volume
V₁=0.024 m³, V₂=0.048 m³.
Compression
Halve volume.
Visualization
Isothermal Processes — Constant Temperature
An isothermal process maintains constant temperature throughout. For an ideal gas, internal energy depends only on T (U = U(T)), so ΔU = 0 and the first law gives Q = W: all heat absorbed is converted to work (expansion) or all work done on the gas appears as heat rejected (compression).
Along an isotherm, the ideal gas law gives PV = nRT = constant — a hyperbola on the P–V diagram. Pressure falls inversely with volume: P₂/P₁ = V₁/V₂. Doubling volume at fixed T halves pressure.
Reversible isothermal work: W = ∫P dV = ∫(nRT/V) dV = nRT ln(V₂/V₁) = nRT ln(P₁/P₂). Use R = 8.314 J/(mol·K), T in kelvin, and V₂/V₁ dimensionless. For 1 mol at 300 K expanding from 24 L to 48 L, W ≈ 8.314 × 300 × ln(2) ≈ 1730 J.
Maintaining constant T requires slow contact with a thermal reservoir (heat bath) so heat can flow in during expansion or out during compression. Fast expansion without heat input is adiabatic, not isothermal.
Isothermal expansion extracts maximum work between two volumes at fixed T compared to adiabatic expansion to the same V₂ (which ends at lower P and T). Carnot cycle uses two isothermal legs at T_hot and T_cold connected by adiabatic steps.
Real gases deviate slightly: intermolecular forces can make ΔU ≠ 0 even at fixed T. Van der Waals and other equations of state give curved isotherms near the critical point.
Key Concepts
- T constant; ideal gas: ΔU = 0
- First law: Q = W (heat ↔ work exchange)
- PV = nRT = const — hyperbola on P–V plot
- W_rev = nRT ln(V₂/V₁) = nRT ln(P₁/P₂)
- Requires thermal reservoir for slow process
- Carnot isotherms at T_hot and T_cold
Real-World Applications
- Idealized lab gas expansion with water bath thermostat
- Carnot engine isothermal heat absorption/rejection steps
- Phase equilibrium at fixed T (vapor pressure, boiling)
- Maximum reversible work calculations in thermodynamics courses
- Class 12 derivation of isothermal work integral
- Industrial gas compression with intercoolers (approximate isothermal stages)
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Physics Equations
Step-by-Step Solution
See how the main results are calculated.
Step 1: Isothermal Condition
Temperature constant → ΔU = 0 for ideal gas.
Equation:
Explanation:
All heat converts to work or vice versa.
Step 2: Ideal Gas at Fixed T
Equation:
Explanation:
Pressure falls as volume rises on expansion.
Step 3: Work Formula
Equation:
Calculation:
Explanation:
Natural log of volume ratio; V₂ > V₁ → positive work by gas.
Step 4: Numerical Work
Calculation:
Result:
Step 5: Heat
Equation:
Calculation:
Explanation:
Heat absorbed equals work done in isothermal expansion.
Step 6: PV Diagram
Path is hyperbola on P–V plot.
Explanation:
Area under curve equals work ∫P dV.
Frequently Asked Questions (FAQ)
Real gases at isothermal?
ΔU not exactly zero if intermolecular forces matter; ideal gas approximation.
Why ln in work formula?
From W = ∫P dV with P = nRT/V.
Isothermal vs isentropic?
Isentropic: reversible adiabatic (Q=0). Isothermal: T fixed (Q≠0).
Units for W?
Joules if nRT in J (use R=8.314, T in K, V ratio dimensionless).
Maximum work between two reservoirs?
Carnot uses isothermal steps at T_hot and T_cold.
Practice MCQs
- Isothermal expansion of ideal gas:
- In isothermal process Q equals:
- Work in expansion V₂ > V₁:
- PV curve for isotherm is:
- To maintain isothermal expansion you need:
- Doubling volume isothermally multiplies pressure by:
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