Lorentz Force Calculator

Find magnetic force on a charge moving perpendicular to B: F = |q|vB

Parameters

Cⓘ
m/sⓘ
Tⓘ
Show Trail

Controls

xⓘ

Calculated Values

Magnetic Force:
0.00;N0.00;N

Examples

Electron in 0.5 T

v = 10⁶ m/s perpendicular to B.

    Proton in 1 T

    Compare heavier mass, same speed.

      Visualization

      Lorentz Force on a Moving Charge

      The Lorentz force is the magnetic force on a point charge q moving with velocity v in a magnetic field B: F⃗ = q(v⃗ × B⃗). The cross product means F is perpendicular to both v and B. Magnitude F = |q|vB sin θ, where θ is the angle between v and B. The most important case for circular motion is θ = 90°, giving F = |q|vB.

      Direction is found with the right-hand rule for positive charge: point thumb along v, curl fingers toward B — palm pushes in the direction of F. Electrons (q < 0) curve the opposite way. In a uniform B field with v ⊥ B, the particle moves in a circle of radius r = mv/(|q|B) because qvB supplies centripetal force mv²/r.

      Crucially, magnetic force does no work on the particle because F ⊥ v at every instant (W = ∫F·v dt = 0). Speed |v| stays constant in a pure magnetic field; only direction changes. If v has a component parallel to B, the path is a helix: circular motion in the perpendicular plane plus uniform drift along B.

      The full electromagnetic Lorentz force includes the electric part: F⃗ = q(E⃗ + v⃗ × B⃗). Velocity selectors in mass spectrometers use crossed E and B so only particles with v = E/B pass straight through; all others are deflected.

      Typical magnitudes: an electron (|q| = 1.6×10⁻¹⁹ C) at v = 10⁶ m/s in B = 0.5 T feels F ≈ 8×10⁻¹⁴ N — small but enough for tight curvature in particle detectors. Earth's field (~50 μT) gently steers cosmic rays; auroras come from charged solar wind in the magnetosphere.

      Class 12 NCERT Moving Charges and Magnetism covers Lorentz force, circular motion in B, and cyclotron frequency ω = |q|B/m. JEE problems often combine energy conservation (electric) with magnetic deflection.

      Key Concepts

      • F⃗ = q(v⃗ × B⃗)
      • F = |q|vB when v ⊥ B
      • Right-hand rule for direction
      • No work: F ⊥ v
      • Circular path r = mv/(|q|B)
      • Helix if v∥B ≠ 0

      Real-World Applications

      • Cyclotron and mass spectrometer
      • Cloud chamber / bubble chamber tracks
      • Magnetic confinement (fusion research)
      • Aurora and Van Allen belts
      • Class 12–JEE moving charge problems

      Explore Further

      More magnetism tools

      Physics Equations

      Lorentz Force:
      F=∣q∣vBF = |q|vB

      Step-by-Step Solution

      See how the main results are calculated.

      1

      Step 1: Vector Form

      Equation:

      F⃗=q v⃗×B⃗\vec{F} = q\,\vec{v} \times \vec{B}

      Explanation:

      Lorentz force is a cross product; magnitude depends on angle between v and B.

      2

      Step 2: Perpendicular Case

      Equation:

      F=∣q∣ v B sin⁡θF = |q|\,v\,B\,\sin\theta

      Explanation:

      When v ⊥ B, sin θ = 1 so F = |q|vB.

      3

      Step 3: Substitute Values

      Calculation:

      F=∣1.0000e−6∣×100×0.5F = |1.0000e-6| \times 100 \times 0.5

      Explanation:

      Charge is positive; use |q| for magnitude.

      4

      Step 4: Numerical Result

      Calculation:

      F=5.0000e−5 NF = 5.0000e-5\ \text{N}

      Result:

      F=5.0000e−5NF = 5.0000e-5 N
      5

      Step 5: Direction (Right-Hand Rule)

      Thumb → v, fingers → B, palm → F (for q > 0).

      Explanation:

      Negative charge deflects opposite to the RHR result.

      6

      Step 6: Physical Check

      F ⊥ v ⇒ magnetic force does no work; speed unchanged in pure B.

      Explanation:

      Particle moves in circle or helix; F provides centripetal acceleration.

      Frequently Asked Questions (FAQ)

      Why does magnetic force do no work?

      F is always perpendicular to v, so F·v = 0. Kinetic energy stays constant in a static B field; only momentum direction changes.

      Relativistic speeds?

      Use relativistic momentum p = γmv and F = dp/dt; radius becomes r = p/(|q|B).

      What if v is parallel to B?

      Magnetic force is zero (sin 0° = 0). Particle moves along field lines at constant speed.

      Units check for F = qvB?

      C × (m/s) × T = C·m/s × (N·s)/(C·m) = N. Tesla is defined so field relations are SI-consistent.

      How to remember direction?

      Use RHR for positive charge; reverse for electrons. Alternatively use vector cross product with unit vectors.

      Practice MCQs

      1. Lorentz force magnitude (v ⊥ B):
      2. Magnetic force on stationary charge:
      3. Work done by magnetic force on particle:
      4. Positive charge in B into page, v right:
      5. Units of B:
      6. Helical path when v has component || B: