Magnetic Force on Wire Calculator
Find force F = BIL when wire is perpendicular to magnetic field
Parameters
Controls
Calculated Values
Examples
Lab wire in horseshoe magnet
B=0.4 T, I=5 A, L=0.3 m.
Strong field
MRI fringe field B=1.5 T, I=2 A, L=0.1 m.
Visualization
Magnetic Force on Current-Carrying Wire
A straight conductor of length L carrying current I in an external magnetic field B experiences a distributed magnetic force. Integrating over the wire gives the total force F⃗ = I L⃗ × B⃗ for a uniform field and straight segment. When the wire is perpendicular to B (θ = 90°), magnitude simplifies to F = BIL — one of the most used formulas in electromagnetism labs.
The direction follows the right-hand rule: point fingers along the current I, curl them toward B; your thumb indicates the force on the wire. Reversing current or flipping B reverses F. When the wire is parallel to B, sin θ = 0 and the force vanishes — no push on a wire running along field lines.
Microscopically, the force on the wire is the sum of Lorentz forces on drifting electrons (and positive ion background). Drift velocity v_d gives F/L = I(B × v̂_d) per unit length, which integrates to BIL for perpendicular geometry.
Parallel current-carrying wires exert forces on each other: parallel currents (same direction) attract; anti-parallel repel. The force per unit length is F/L = μ₀I₁I₂/(2πd) where d is separation. This underlies the SI definition of the ampere.
Practical example: B = 0.4 T, I = 5 A, L = 0.3 m gives F = 0.6 N — about the weight of 60 g. Loudspeakers and DC motors use many such segments in a coil to produce large net forces and torques τ = NIAB sin θ.
Class 12 problems link straight-wire force to galvanometers, force balances, and rail-gun concepts. Always distinguish force on wire (external B) from field produced by the wire itself (Ampère's law).
Key Concepts
- F⃗ = I L⃗ × B⃗
- F = BIL (wire ⊥ B)
- RHR: I → curl B → thumb F
- Parallel wires: same I attract
- F = 0 when wire ∥ B
Real-World Applications
- DC motors and loudspeakers
- Magnetic force balances (lab)
- Parallel-wire ampere definition
- Maglev and rail guns (concept)
- Class 12 force-on-conductor numericals
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Physics Equations
Step-by-Step Solution
See how the main results are calculated.
Step 1: Force on Conductor
Equation:
Explanation:
Each current element IL feels a magnetic force in external field B.
Step 2: Straight Wire (θ = 90°)
Equation:
Explanation:
Wire perpendicular to B gives maximum force.
Step 3: List Given Quantities
Result:
Step 4: Multiply
Calculation:
Result:
Step 5: Direction
RHR: fingers along I, curl toward B, thumb = force on wire.
Explanation:
If wire ∥ B, then F = 0.
Step 6: Connection to Motors
Equation:
Explanation:
Force on coil sides produces rotation in motors and galvanometers.
Frequently Asked Questions (FAQ)
Curved or bent wire?
Use dF⃗ = I dL⃗ × B⃗ and integrate along the path. For uniform B and semicircle, geometry factors appear in the integral.
Does the wire's own field matter?
F = BIL uses external B only. The field from the wire itself does not exert a net force on the same wire.
Why do parallel currents attract?
Each wire creates B at the other; the Lorentz force on the second wire points toward the first when currents are parallel.
AC current in B?
Use instantaneous I(t); force oscillates at twice the frequency if B is constant and I is sinusoidal.
Practice MCQs
- Force on wire (I ⊥ B):
- Doubling current doubles:
- Wire parallel to B:
- Same-direction parallel currents:
- Motor converts:
- F units:
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