Stefan–Boltzmann Radiation Calculator

Calculate radiated power P = εσAT⁴ (T in kelvin)

Parameters

Kⓘ
m²ⓘ
ⓘ
Show Trail

Controls

xⓘ

Calculated Values

Radiated Power P:
318.94;W318.94;W
Radiative Flux:
3189.38;W/m23189.38;W/m²

Examples

Hot plate

T=500 K, A=0.1 m², ε=0.9.

    Human skin approx

    T=310 K, A=1.7 m², ε=0.98.

      Visualization

      Stefan–Boltzmann Law — Thermal Radiation Power

      All objects with T > 0 K emit electromagnetic thermal radiation. The Stefan–Boltzmann law (Stefan 1879; Boltzmann 1884) gives the total power radiated per unit time from a surface: P = εσAT⁴, where σ = 5.670374×10⁻⁸ W/(m²·K⁴) is the Stefan–Boltzmann constant, A is surface area (m²), T is absolute temperature (K), and ε is emissivity (0 ≤ ε ≤ 1).

      A perfect blackbody has ε = 1 and emits the maximum possible thermal radiation at temperature T. Real surfaces have ε < 1: polished aluminum ~0.05, oxidized iron ~0.8, human skin ~0.98, matte black paint ~0.95. Emissivity equals absorptivity at thermal equilibrium (Kirchhoff's law).

      The T⁴ dependence is extremely strong: doubling absolute temperature multiplies radiated power by 2⁴ = 16. A 500 K object radiates roughly 16× more power than at 250 K (same area and ε). This explains why hot objects glow visibly and cool rapidly at high T.

      Net radiative heat transfer between an object at T and large surroundings at T_env: P_net = εσA(T⁴ − T_env⁴). If surroundings are colder, net power is positive (object cools by radiation). In a vacuum, radiation is often the only heat loss mode (spacecraft, thermos flask silvering reduces ε).

      Stefan–Boltzmann gives total power across all wavelengths. Wien's displacement law λ_max T = b (b ≈ 2.898×10⁻³ m·K) gives the peak emission wavelength. Planck's law describes the full spectrum; integrating Planck over all λ yields σT⁴.

      Applications range from stellar astrophysics (luminosity L ∝ R²T⁴ for stars) to building energy loss, infrared cameras, and furnace design. At room temperature (~300 K), radiation is often smaller than convection; above ~500 K it dominates cooling.

      Key Concepts

      • P = εσAT⁴ — total radiated power (W)
      • σ = 5.67×10⁻⁸ W/(m²·K⁴); T in kelvin only
      • ε: emissivity (0–1); blackbody ε = 1
      • Net radiation: P_net ∝ T⁴ − T_env⁴
      • Doubling T multiplies P by 16 (T⁴ law)
      • Wien: λ_max ∝ 1/T; Planck → Stefan–Boltzmann

      Real-World Applications

      • Stellar luminosity and effective temperature (astrophysics)
      • Building envelope radiative heat loss and low-e windows
      • Infrared thermography and night vision
      • Industrial furnace and kiln heat transfer
      • Earth's energy balance and greenhouse effect (outgoing longwave radiation)
      • Thermos flask design (low-ε reflective surfaces reduce radiative loss)

      Explore Further

      More thermodynamics tools

      Physics Equations

      Stefan–Boltzmann:
      P=εσAT4P = \varepsilon \sigma A T^4
      σ:
      σ=5.67×10−8 W/(m2K4)\sigma = 5.67 \times 10^{-8} \text{ W/(m}^2\text{K}^4\text{)}

      Step-by-Step Solution

      See how the main results are calculated.

      1

      Step 1: Stefan–Boltzmann Law

      Equation:

      P=εσAT4P = \varepsilon \sigma A T^4

      Explanation:

      Power radiated by blackbody surface; T in kelvin.

      2

      Step 2: Constants

      Calculation:

      σ=5.67×10−8 W/(m2K4),ε=0.9\sigma = 5.67 \times 10^{-8} \text{ W/(m}^2\text{K}^4\text{)}, \quad \varepsilon = 0.9

      Explanation:

      ε = 1 for ideal blackbody; 0.9–0.95 for dark surfaces.

      3

      Step 3: T⁴

      Calculation:

      T4=(500)4=6.2500e+10 K4T^4 = (500)^4 = 6.2500e+10 \text{ K}^4

      Explanation:

      Radiated power very sensitive to temperature.

      4

      Step 4: Power

      Calculation:

      P=0.9×5.67e−8×0.1×6.2500e+10=3.1894e+2 WP = 0.9 \times 5.67e-8 \times 0.1 \times 6.2500e+10 = 3.1894e+2 \text{ W}

      Result:

      P=3.1894e+2WP = 3.1894e+2 W
      5

      Step 5: Doubling T

      Effect of temperature change.

      Explanation:

      Doubling T (K) multiplies radiated power by 2⁴ = 16.

      6

      Step 6: Applications

      Stars, furnaces, thermal cameras.

      Explanation:

      Net radiation uses T⁴ difference between body and surroundings.

      Frequently Asked Questions (FAQ)

      Difference from conduction?

      Radiation needs no medium; conduction needs material contact.

      Why T⁴?

      From quantum statistics integration of Planck spectrum — beyond intro level.

      Emissivity of polished metal?

      Low ε (~0.05) — poor emitter, good reflector.

      Greenhouse effect?

      Atmosphere reduces net radiative loss from Earth surface.

      Can P be negative?

      Net power can be negative if surroundings hotter — net absorption.

      Practice MCQs

      1. Doubling absolute temperature multiplies radiated power by:
      2. Stefan–Boltzmann uses temperature in:
      3. Perfect blackbody has ε =
      4. σ has units:
      5. Larger surface area A:
      6. Hot object cools mainly by radiation when: