Cyclotron Radius Calculator

Find orbital radius r = mv/(|q|B) in uniform magnetic field

Parameters

kgⓘ
m/sⓘ
Cⓘ
Tⓘ
Show Trail

Controls

xⓘ

Calculated Values

Orbit Radius:
0.00;m0.00;m

Examples

Electron in 1 T

v=10⁶ m/s.

    Visualization

    Cyclotron Radius and Motion in B

    When a charged particle enters a uniform magnetic field with velocity perpendicular to B, Lorentz force qvB provides centripetal acceleration: qvB = mv²/r. Solving gives orbit radius r = mv/(|q|B). Heavier particles or higher speeds curve more gently; stronger B tightens the circle.

    The motion is uniform circular with angular frequency ω = |q|B/m and period T = 2πm/(|q|B), independent of speed v in classical mechanics — the basis of the cyclotron accelerator (particles gain speed each crossing of the gap while orbital period stays fixed).

    Electron example: m = 9.11×10⁻³¹ kg, v = 10⁶ m/s, B = 1 T gives r ≈ 5.7×10⁻³ m = 5.7 mm. Proton at same v and B has r ≈ 10⁴ times larger because of greater mass.

    If velocity has a component v∥ along B, the path is a helix: radius r from the perpendicular part v⊥, pitch determined by v∥. Velocity selectors use crossed E and B so only particles with v = E/B enter the deflection region undeflected.

    Mass spectrometers measure r (or time of flight) to identify ions by mass-to-charge ratio. Cloud chambers and bubble chambers show curved tracks whose curvature reveals momentum.

    At relativistic energies use r = p/(|q|B) with p = γmv. Synchrotrons vary B and RF frequency as particle mass increases with energy.

    Key Concepts

    • qvB = mv²/r
    • r = mv/(|q|B)
    • ω = |q|B/m, T = 2π/ω
    • Independent of v (classical)
    • Helix if v∥ ≠ 0
    • Relativistic: r = p/(|q|B)

    Real-World Applications

    • Cyclotron and synchrotron
    • Mass spectrometry
    • Particle detector tracking
    • Proton therapy beam optics
    • Cloud chamber demos
    • Class 12 circular motion in B

    Explore Further

    More magnetism tools

    Physics Equations

    Radius:
    r=mv∣q∣Br = \frac{mv}{|q|B}

    Step-by-Step Solution

    See how the main results are calculated.

    1

    Step 1: Balance Forces

    Equation:

    qvB=mv2rqvB = \frac{mv^2}{r}

    Explanation:

    Magnetic force provides centripetal force for circular motion (v ⊥ B).

    2

    Step 2: Solve for Radius

    Equation:

    r=mv∣q∣Br = \frac{mv}{|q|B}

    Explanation:

    Heavier or faster particles curve less; stronger B tightens orbit.

    3

    Step 3: Substitute

    Calculation:

    r=9.1100e−31×10000001.6000e−19×1r = \frac{9.1100e-31 \times 1000000}{1.6000e-19 \times 1}

    Explanation:

    Use |q| in denominator.

    4

    Step 4: Radius

    Calculation:

    r=5.6938e−6 mr = 5.6938e-6\ \text{m}

    Result:

    r=5.6938e−6mr = 5.6938e-6 m
    5

    Step 5: Angular Frequency

    Calculation:

    ω=∣q∣Bm=1.7563e+11 rad/s,T=2πω=3.5775e−11 s\omega = \frac{|q|B}{m} = 1.7563e+11\ \text{rad/s},\quad T = \frac{2\pi}{\omega} = 3.5775e-11\ \text{s}

    Explanation:

    Cyclotron frequency independent of v (non-relativistic).

    6

    Step 6: Mass Spectrometer

    Same v and B → different r for different m/q identifies species.

    Explanation:

    Velocity selector ensures common v before entering B region.

    Frequently Asked Questions (FAQ)

    Component along B?

    Helical path; r from perpendicular component only.

    Relativistic?

    Use p = γmv in r = p/(qB).

    Practice MCQs

    1. Radius in uniform B:
    2. Double speed v:
    3. Double B:
    4. Cyclotron frequency ω:
    5. Electron vs proton same v,B:
    6. Velocity selector uses: