Torque on Current Loop Calculator

Find torque τ = NIAB sin θ on a coil in uniform B

Parameters

ⓘ
Aⓘ
m²ⓘ
Tⓘ
°ⓘ
Show Trail

Controls

xⓘ

Calculated Values

Torque:
0.25;N⋅m0.25;N·m

Examples

N=50, I=2, A=0.01, B=0.5

θ=30°.

    Visualization

    Torque on a Current Loop in Magnetic Field

    A current loop in a uniform magnetic field is a magnetic dipole. For N turns, area A, current I, in field B, the torque magnitude is τ = NIAB sin θ, where θ is the angle between the magnetic dipole moment μ (normal to the loop) and B.

    The dipole moment vector has magnitude μ = NIA and direction given by the right-hand rule for the circulating current. Vector form: τ⃗ = μ⃗ × B⃗. Maximum torque τ_max = NIAB occurs at θ = 90° (plane of coil parallel to B). Zero torque at θ = 0° when the normal aligns with B.

    Potential energy of a dipole in a field is U = −μ⃗·B⃗ = −μB cos θ. Stable equilibrium at θ = 0 (μ parallel B); unstable at θ = 180°. A compass needle is a magnetic dipole aligning with Earth's field.

    DC motors exploit torque on a multi-turn coil. A split-ring commutator reverses current every half rotation so torque always aids the same spin direction. Without it, the coil would oscillate about equilibrium instead of continuous rotation.

    Galvanometers use a coil in a radial B field so τ = NIAB is constant for small deflections; pointer angle measures current. Moving-coil meters are sensitive and linear for small angles.

    Example: N = 50, I = 2 A, A = 0.01 m², B = 0.5 T, θ = 30° gives τ = 50×2×0.01×0.5×0.5 = 0.25 N·m.

    Key Concepts

    • τ = NIAB sin θ
    • μ⃗ = NIA (dipole moment)
    • τ⃗ = μ⃗ × B⃗
    • U = −μB cos θ
    • τ_max at θ = 90°
    • Commutator in DC motors

    Real-World Applications

    • DC motors and fans
    • Moving-coil galvanometers
    • Compass and dipole alignment
    • MRI spin torque (advanced)
    • Class 12 torque-on-coil problems

    Explore Further

    More magnetism tools

    Physics Equations

    Torque:
    τ=NIABsin⁡θ\tau = NIAB\sin\theta

    Step-by-Step Solution

    See how the main results are calculated.

    1

    Step 1: Magnetic Dipole Moment

    Equation:

    μ⃗=NIA⃗\vec{\mu} = N I \vec{A}

    Explanation:

    N turns, current I, area vector A (magnitude A, direction = normal).

    2

    Step 2: Torque

    Equation:

    τ⃗=μ⃗×B⃗⇒τ=NIABsin⁡θ\vec{\tau} = \vec{\mu} \times \vec{B} \Rightarrow \tau = NIAB\sin\theta

    Explanation:

    θ = angle between μ and B.

    3

    Step 3: sin θ

    Calculation:

    θ=30°⇒sin⁡θ=0.5000\theta = 30° \Rightarrow \sin\theta = 0.5000
    4

    Step 4: Calculate τ

    Calculation:

    τ=50×2×0.01×0.5×0.5000=2.5000e−1 N\cdotpm\tau = 50 \times 2 \times 0.01 \times 0.5 \times 0.5000 = 2.5000e-1\ \text{N·m}

    Result:

    τ=2.5000e−1N⋅mτ = 2.5000e-1 N·m
    5

    Step 5: Maximum Torque

    Calculation:

    τmax⁡=NIAB=5.0000e−1 N\cdotpm at θ=90°\tau_{\max} = NIAB = 5.0000e-1\ \text{N·m at }\theta = 90°

    Explanation:

    Zero torque when coil plane is perpendicular to B (θ = 0).

    6

    Step 6: DC Motor

    Commutator reverses I every half turn so τ always aids rotation.

    Explanation:

    Galvanometer uses same principle for measuring current.

    Frequently Asked Questions (FAQ)

    Non-rectangular coil?

    Use A as area; τ = NIAB sin θ still applies for uniform B.

    Energy minimum?

    U = −μB cos θ; stable when μ aligned with B.

    Practice MCQs

    1. Torque on coil:
    2. τ maximum when:
    3. Magnetic dipole moment:
    4. Doubling N and I:
    5. Motor needs commutator to:
    6. Units of τ: